a particle starts from rest has a constant accleration of 4m/s2 for 4s. it then retard uniformly for next 8s and comes to rest . average accleration during motion of particle is0
Answers (2)
Student Expert
27th Oct, 2019
v = 0 m/s
u = 10 m/s
s = 20 m.
v^2 = u^2 + 2as
Or, 0 = 100 + 40a
Or, a = - 100 /40 = - 5/2.
.°. a = - 5/2 m/s^2
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Second case,
v = 0 m/s
u = 20 m/s
a = - 5/2 m/s^2
v^2 = u^2 + 2as
Or, 0 = 400 - 5s
Or, s = 400/5 = 80.
.°. The stopping distance will be 80 m.
Thank you.
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Student Expert
27th Oct, 2019
Hello there!
Greetings !
I am extremely sorry to tell you but you haven't completed your question, what did not mention what is needed to be found in the question, let me know what is to be found in the questions so that I can help you by giving you its solution.
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