a particle starts with some initial velocity and constant acceleration in some direction.distance travelled by the particle in first 4 sec is 100 m and in next 4 sec is 140m. find velocity of the particle at 6 second?
Recommended : Get important details about Saveetha Engineering College, Chennai.
Download Brochure
Answer (1)
30th Nov, 2019
Using s = ut + 1/2a(t^2), we can write
100 = 4u + 8a
=> u + 2a = 25 ------(1)
Also, Since the distance traveled in the next 4 seconds is 140m, the total distance traveled in the 8 seconds is 240 m. So we can write
240 = 8u + 32a
=> u +4a = 30 ------(2)
Solving Eq.1 and 2 we can say,
a = 5/2 m/s/s and u = 20 m/s
Hence the velocity at t=6 sec, is 20 + 5/2*6 = 35m/s.
Comments (0)
