Question : A photographer is allowed a discount of 10% on the advertised price of a camera. The price (in Rs.) that must be marked on the camera, which cost him Rs. 600, to make a profit of 20% would be:
Option 1: 650
Option 2: 800
Option 3: 700
Option 4: 850
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Correct Answer: 800
Solution :
Let the marked price of the camera be Rs. $x$.
According to the question,
(100 – 10)% of $x$ = 120% of 600 (Since Selling price = Cost price + Profit = Marked price – Discount)
⇒ $x$ × 90 = 600 × 120
⇒ $x$ = $\frac{600×120}{90}$ = Rs. 800
Hence, the correct answer is 800.
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