Correct Answer: Circle

Solution : The length of the wire is the same in all three cases, so it becomes the perimeter of each shape.
(1). For an equilateral triangle with side length $a$, the perimeter = $3a$
$a = \frac{132}{3} = 44$ cm
The area of an equilateral triangle $ = \frac{\sqrt{3}}{4}a^2 = \frac{\sqrt{3}}{4}(44)^2= 838.32$ cm ²
(2). For a square with side length $a$, the perimeter = $4a$. So, $a = \frac{132}{4} = 33$ cm
The area of a square $ = a^2 = (33)^2= 1089$ cm ²
(3). For a circle with radius $r$, the circumference = $2\pi r$
$2\pi r=132$
⇒ $r = \frac{132}{2\pi} $
The area of a circle $ = \pi r^2 = \pi \left(\frac{132}{2\pi}\right)^2= 1386$ cm ²
The area will be largest in the shape of a circle.
Hence, the correct answer is 'Circle'.