A point charge of 2 coulomb is at centre of cubic gaussian surface 9cm on edge. what is the net electric flux through the surface
Hello,
The net electric flux through a closed Gaussian surface depends on the enclosed charge. By Gauss's law, the electric flux (Φ) is given by:
\[
\Phi = \frac{q}{\epsilon_0}
\]
where \( q \) is the enclosed charge and \( \epsilon_0 \) is the permittivity of free space (\(8.85 \times 10^{-12} \, \text{C}^2/\text{Nm}^2\)).
For a 2 C charge:
\[
\Phi = \frac{2}{8.85 \times 10^{-12}} \approx 2.26 \times 10^{11} \, \text{Nm}^2/\text{C}
\]
The net flux depends only on the charge, not the cube size.
Hope this helps you,
Thank you