Question : A point D is taken from the side BC of a right-angled triangle ABC, where AB is hypotenuse. Then:
Option 1: AB2 + CD2 = BC2 + AD2
Option 2: CD2 + BD2 = 2AD2
Option 3: AB2 + AC2 = 2AD2
Option 4: AB2 = AD2 + BD2
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Correct Answer: AB 2 + CD 2 = BC 2 + AD 2
Solution : According to the question, Using Pythagoras theorem, In $\triangle$ABC AB 2 = AC 2 + BC 2 ...........................................(i) In $\triangle$ACD AD 2 = AC 2 + CD 2 AC 2 = AD 2 – CD 2 ...........................................(ii) Put the value of AC 2 in equation (i) AB 2 = AD 2 – CD 2 + BC 2 AB 2 + CD 2 = AD 2 + BC 2 Hence, the correct answer is AB 2 + CD 2 = BC 2 + AD 2 .
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