Question : A policeman follows a thief, who is 1250 m ahead of him. The policeman and the thief run at speeds of 10 km/h, and 8 km/ h respectively. The distance (in km) run by the thief before he is nabbed by the policeman is:
Option 1: 7 km
Option 2: 4 km
Option 3: 5 km
Option 4: 6 km
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: 5 km
Solution :
Given: Distance between the policeman and the thief = 1250 m
Speed of the policeman = 10 km//h = $10×\frac{5}{18}=\frac{25}{9}$ m/s
Speed of the thief = 8 km//h = $8×\frac{5}{18}=\frac{20}{9}$ m/s
Relative speed of the policeman and the thief $=\frac{25}{9}–\frac{20}{9}=\frac{5}{9}$ m/s
Time taken by the policeman to catch the thief $=\frac{1250}{\frac{5}{9}}=2250$ sec
Distance travelled by thief before getting caught $=\frac{20}{9}×2250$
= 5000 m = 5 km
Hence, the correct answer is 5 km.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
