a pond has a nice layer of thickness present if ke of 0.005 CGS units surface temperature of surroundings is -20 degrees celsius city of ice is 0.9 gram per CC the time taken for the thickness to increase 1 cm is
Answer (1)
29th Nov, 2020
Hello,
Let a=surface area of ice
t=thickness(1 cm)
Hence mass m=density*a*1=0.9*a*1
=0.9a grams
The heat required= Q=mL
=0.9A*80=72 calories
Mean thickness=
d=3+(4/2)=3.5 cm
Hence Q is given by-
Q=(K*a*(delta thetha))/d
t = Qd/K*a*(Delta thetha)
= 72A x 3.5 / 0.005 x A x 20
=2520 seconds.
Hence total time taken would be 2520 seconds or 2520/60=42 minutes
Hope this helps.
Comments (0)
Related Questions
Where are CGS units used?
6 Views
