a quantity of perfect gas at 10 degree Celsius is adiabatically compressed to one third of its initial volume calculate the final temperature use Gamma equal to 1.5
Answer (1)
5th Nov, 2020
Dear student,
T1 = 10 = 283K
Let initial volume be V1 and final be V2 .
Now, as gas is adiabatically compressed to one third of it's original volume then :
V2 = 1/3 of V1
That is :-
V2 / V1 = 1/3
And, gamma = 1.5
And since the gas is compressed, so we will use
T2 (V2)^(gamma - 1) = T1 (V1)^(gamma - 1)
Therefore it becomes -
T2 = T1 (V1/V2)^(gamma - 1)
T2 = 283 (3)^0.5 = 283√3
Therefore the final temperature is :-
T2 = 490.17K
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