Question : A right pyramid stands on a base 16 cm square and its height is 15 cm. The area (in cm2) of its slant surface is:
Option 1: 514
Option 2: 544
Option 3: 344
Option 4: 444
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Correct Answer: 544
Solution :
Side of a square, $a$ = 16 cm
Height, $h$ = 15 cm
Perimeter $= 4a = 4 × 16 = 64$ cm
Slant height of pyramid, $l = \sqrt{h^{2}+(\frac{a}{2})^{2}} = \sqrt{15^{2}+8^{2}} = 17$ cm
Lateral surface area = $\frac{1}{2}$ × Perimeter of base × Slant height
= $\frac{1}{2}×64×17$
= 544 cm
2
Hence, the correct answer is 544.
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