A rod of mass m and length hinged at its centre is placed on a horizontal surface. A bullet of mass m moving with velocity v strikes the end A of the rod and gets embedded in it. The angular velocity with which the system rotates about its centre of mass after the bullet strikes the rod
Answer (1)
Student Expert
27th Oct, 2019
These are some of the basic questions. Practice more such problems from mcq books like marvel or USS to strengthen your grip over the topic and the subject.
We know that momentum must be conserved .
Thus the momentum of that part of the rod is
mu .
And Angular momentum = rP
= (L/2)mu
= ωI = ω(∫( 2M/L)r² dr + m(L/2)²)
= ω((2M/L)(L/2)³/3 + m(L/2)²)
Solve the equation between the first and last line , and you will have your answer .
Best wishes. Thank you.
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