A Set A (X:XER, X2-16 and 2 x = 6}
Hello Siddhant,
Since, x^2 = 16, which implies, x = ± 4 and 2x = 6, which implies, x = 3. Hence, no value of 'x' is satisfied. Therefore, A = phi.
I hope you understood the solution for the same. If you have any queries, do ask me in the comment section.
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