To find the impedance of the circuit, we first calculate X L and X C .

X L = 2 π ν L

= 2 × 3.14 × 50 × 25.48 × 10 –3 W = 8 W

X C = (1/2 π ν C)

= (1/ 2 × 3.14 × 50 × 796 x 10 -6 )

= 4Ω

Therefore,

Z = √R 2 + (X L − X C ) 2 =√(3) 2 + (8 − 4) 2

= 5 Ω (Ans)

Phase difference, f = tan –1 (X C – X L )/(R)

=tan -1 ((4-8)/(3))

=-53.1 0

Power factor = cos = cos53.1° = 0.6 (Ans)