Question : A slope of line AB is $-\frac{2}{3}$. Co-ordinates of points A and B are $(x,–3)$ and $(5, 2)$, respectively. What is the value of $x$?
Option 1: 4
Option 2: –14
Option 3: 12.5
Option 4: –4
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 12.5
Solution : Given: A slope of line AB is $-\frac{2}{3}$. Co-ordinates of points A and B are $(x,–3)$ and $(5, 2)$, respectively. Slope of line(m) $=\frac{y_{2}–y_{1}}{x_{2}–x_{1}}$ $⇒-\frac{2}{3}= \frac{2–(–3)}{5–x}$ $⇒-\frac{2}{3}= \frac{2+3}{5–x}$ $⇒-\frac{2}{3}= \frac{5}{5–x}$ $⇒-10+2x=15$ $\therefore x=12.5$ Hence, the correct answer is 12.5.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : For the triangle $PQR$, find the equation of altitude $PS$, if the co-ordinates of $P, Q, R$ are (1, 2), (2, –1), and (0, 5), respectively.
Question : If $X$ is 20% less than $Y$, then find the values of$\frac{Y–X}{Y}$ and $\frac{X}{X–Y}$.
Question : If $x=\frac{4\sqrt{15}}{\sqrt{5}+\sqrt{3}}$, the value of $\frac{x+\sqrt{20}}{x–\sqrt{20}}+\frac{x+\sqrt{12}}{x–\sqrt{12}}$ is:
Question : If $\frac{x}{y}=\frac{4}{5}$, then the value of $(\frac{4}{7}+\frac{2y–x}{2y+x})$ is:
Question : If $x+\frac{1}{x}=3$, then the value of $\frac{3x^{2}-4x+3}{x^{2}-x+1}$ is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile