A solution is prepared by adding 6g of glucose in 18g of water. The mass percent of solute in solution will be a).75% b ).25% c ).33.33% d).50%
Hey!
As we know,
Mass percent of solute = (mass of solute/mass of solution) * 100
Given: Mass of solute (glucose) = 6 g
Mass of solvent (water) = 18 g
Mass of solution (glucose + water) = 6 + 18 = 24g
Therefore, Mass percent of solute = (6/18)*100
which is , (1/3)*100
Mass percent of solute = 33.33%
Thankyou