Hello!!!
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The radius of the bigger sphere=r
let x be the distance between center of mass from the original center of the sphere after the smaller sphere has cut.
let the density of the bigger sphere be d
mass of the bigger sphere = 4/3* π r^3d
mass of the smaller sphere= 4/3* π(r/2)^3d
mass of the remaining sphere= 4/3* π r^3d - 4/3* π(r/2)^3d
on solving,we get,,,, 7/6* π r^3d
position of the center of mass of the complete sphere=0
=-x*7/6 π r^3d+r/2*4/3 π (r/2)^3d=0
on solving we get,x=r/14
Hope it helps!!!
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