749 Views

A sphere of diameter r is cut from a sphere of radius r such that the centre of mass the remaining mass be at maximum distance from orinal center. the distance is


ABHILIPSHA BARAL 6th Jun, 2020
Answer (1)
Mounika Sonti 6th Jun, 2020

Hello!!!

Hope you are doing great!!!

The radius of the bigger sphere=r

let x be the distance between center of mass from the original center of the sphere after the smaller sphere has cut.

let the density of the bigger sphere be d

mass of the bigger sphere = 4/3* π r^3d

mass of the smaller sphere= 4/3* π(r/2)^3d

mass of the remaining sphere= 4/3* π r^3d - 4/3* π(r/2)^3d

on solving,we get,,,, 7/6* π r^3d

position of the center of mass of the complete sphere=0

=-x*7/6 π r^3d+r/2*4/3 π (r/2)^3d=0

on solving we get,x=r/14


Hope it helps!!!

Related Questions

UPES Integrated LLB Admission...
Apply
Ranked #28 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS University Rankings | 16.6 LPA Highest CTC
SLAT 2025 - The Symbiosis Law...
Apply
Conducted by Symbiosis International (Deemed University) | Ranked #5 in Law by NIRF | Ranked #2 among best Pvt Universities by QS World Rankings
Jindal Global Law School Admi...
Apply
Ranked #1 Law School in India & South Asia by QS- World University Rankings | Merit cum means scholarships
Symbiosis Law School Pune Adm...
Apply
NAAC A++ Accredited | Ranked #5 by NIRF
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC
ISBR Business School PGDM Adm...
Apply
Ranked as Platinum Institute by AICTE for 5 years in a row | Awarded Best Business School of the Year
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books