a spring of force constant k is cut into lenghts of ratio 1:2:3 then we get three springs of length l/6, 2l/6, 3l/6 how did we get this?
Answer (1)
22nd Aug, 2020
Hello,
Assume the length of the spring to be 'l'
Now the ratios of lengths in which the spring is cut is 1:2:3
That means the length of the three new springs will be x, 2x and 3x where x is equal to some constant.
Therefore, 1x + 2x + 3x = l
= 6x = l
= x = l/6
Now length of new springs will be l/6, 2l/6 and 3l/6
(Substituting the value of x = l/6)
Hope it is clear now.
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3 Comments
Comments (3)
thanks alot ...
it really helped me😇
it really helped me😇
Reply
Prabhav Sharma
thank you....
how do u clear all ur physics concepts?
how do u clear all ur physics concepts?
