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a stone that wieghs 2kg is thrown vertically upwards with a kinetic energy of 250 joule how high will the stone go before it returns to the ground ? you may assume all the kinetic energy of the stone is changed into potential energy (1 kg f is equal to 10 Newton)


Syed . Quadri 4th Apr, 2020
Answer (1)
Mounika Sonti 21st May, 2020

Hello!!!!

Hope you are doing great!!

Given weight of the stone = 2 kg

kinetic energy = 250J

we know that , kinetic energy = 1/2 mv^2

1/2mv^2 = 250 J

1/2 (2)v^2 = 250

v^2 = 250

In the problem ,, given ,, Kinetic energy = potential energy

1/2mv^2 = mgh

v^2 / 2 = gh

v^2 / 2g = h

h=250/2(9.8)

h=12.755m

Therefore, height = 12.755m

Hope it helps!!!

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