#IT
127 Views

a stone that wieghs 2kg is thrown vertically upwards with a kinetic energy of 250 joule how high will the stone go before it returns to the ground ? you may assume all the kinetic energy of the stone is changed into potential energy (1 kg f is equal to 10 Newton)


Syed . Quadri 4th Apr, 2020
Answer (1)
Mounika Sonti 21st May, 2020

Hello!!!!

Hope you are doing great!!

Given weight of the stone = 2 kg

kinetic energy = 250J

we know that , kinetic energy = 1/2 mv^2

1/2mv^2 = 250 J

1/2 (2)v^2 = 250

v^2 = 250

In the problem ,, given ,, Kinetic energy = potential energy

1/2mv^2 = mgh

v^2 / 2 = gh

v^2 / 2g = h

h=250/2(9.8)

h=12.755m

Therefore, height = 12.755m

Hope it helps!!!

Related Questions

UPES Integrated LLB Admission...
Apply
Ranked #28 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS University Rankings | 16.6 LPA Highest CTC
SLAT 2025 - The Symbiosis Law...
Apply
Conducted by Symbiosis International (Deemed University) | Ranked #5 in Law by NIRF | Ranked #2 among best Pvt Universities by QS World Rankings
Jindal Global Law School Admi...
Apply
Ranked #1 Law School in India & South Asia by QS- World University Rankings | Merit cum means scholarships
Symbiosis Law School Pune Adm...
Apply
NAAC A++ Accredited | Ranked #5 by NIRF
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC
ISBR Business School PGDM Adm...
Apply
Ranked as Platinum Institute by AICTE for 5 years in a row | Awarded Best Business School of the Year
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books