Question : A string of length 24 cm is bent first into a square and then into a right-angled by keeping one side of the square fixed as its base. Then the area of a triangle equals to:
Option 1: 24 cm2
Option 2: 60 cm2
Option 3: 40 cm2
Option 4: 28 cm2
Correct Answer: 24 cm 2
Solution :
The side of the square = $\frac{24}{4}$ = 6 cm
The base of the triangle is 6 cm.
The perimeter of the triangle is 24 cm.
Using the Pythagoras triplets (i.e. 6, 8, and 10).
So, the height of the triangle is 8 cm.
The area of a triangle = $\frac{1}{2}$ × 6 cm × 8 cm
Hence, the correct answer is 24 cm
2
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