Question : A sum (in INR) is distributed between A, B, and C in the ratio 9 : 6 : 11. If A gives INR 500 from his share to C, the ratio of shares of A, B, and C becomes 4 : 3 : 6. What is the sum of shares (in INR) of B and C, in the beginning?
Option 1: INR 8,500
Option 2: INR 9,100
Option 3: INR 7,800
Option 4: INR 7,500
Correct Answer: INR 8,500
Solution :
Given: A sum (in INR) is distributed between A, B, and C in the ratio 9 : 6 : 11.
Let the share of A, B and C be $9x,6x$ and $11x$.
A gives INR 500 from his share to C, and the ratio of shares of A, B, and C becomes 4 : 3 : 6.
According to the question,
$\frac{9x-500}{11x+500}=\frac{4}{6}$
⇒ $\frac{9x-500}{11x+500}=\frac{2}{3}$
⇒ $27x-1500=22x+1000$
⇒ $27x-22x=1000+1500$
⇒ $5x=2500$
⇒ $x=$ INR 500
In the beginning, the sum of shares (in INR) of B and C $=6x+11x=17x$
$=17\times 500=$ INR 8,500
Hence, the correct answer is INR 8,500.
Related Questions
Know More about
Staff Selection Commission Sub Inspector ...
Result | Eligibility | Application | Selection Process | Cutoff | Admit Card | Preparation Tips
Get Updates Brochure
Your Staff Selection Commission Sub Inspector Exam brochure has been successfully mailed to your registered email id “”.
