Question : A sum of Rs. 730 was divided among A, B, and C in such a way that if A gets Rs. 3, B gets Rs. 4, and if B gets Rs. 3.50, C gets Rs. 3. The share of B exceeds that of C by:
Option 1: Rs. 30
Option 2: Rs. 40
Option 3: Rs. 70
Option 4: Rs. 210
Correct Answer: Rs. 40
Solution : A : B = 3 : 4 = 21 : 28 B : C = 3.5 : 3 = 7 : 6 = 28 : 24 So, A : B : C = 21 : 28 : 24 Let's assume A, B, and C are in ratio $21x, 28x$, and $24x$. ⇒ $21x+28x+24x = 730$ ⇒ $73x = 730$ $\therefore x= 10$ Thus, the difference between B and C $=28x-24x=4x = 4 × 10 = 40$ Hence, the correct answer is Rs. 40.
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