Question : A sum of Rs. 730 was divided among A, B and C in such a way that if A gets Rs. 3, then B gets Rs. 4. And if B gets Rs. 3.50, then C gets Rs. 3. The share of B exceeds that of C by:
Option 1: Rs. 30
Option 2: Rs. 40
Option 3: Rs. 70
Option 4: Rs. 210
Correct Answer: Rs. 40
Solution :
Given: A sum of Rs. 730 was divided among A, B and C in such a way that if A gets Rs. 3, then B gets Rs. 4. And if B gets Rs. 3.50, then C gets Rs. 3.
So, A : B = 3 : 4 = 21 : 28
and B : C = 3.5 : 3 = 7 : 6 = 28 : 24
Their combined ratio will be,
A : B : C = 21 : 28 : 24
The sum of the terms of the ratio is (21 + 28 + 24) = 73
B's share exceeds C's by $(\frac{28–24}{73})$ × 730 = Rs. 40
Hence, the correct answer is Rs. 40.
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