Question : A tangent AB at point A of a circle of radius 6 cm meets a line through the centre O at point B. If OB = 10 cm, then the length of AB (in cm) is equal to:
Option 1: 5
Option 2: 6
Option 3: 4
Option 4: 8
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: 8
Solution :
Given, AB is a tangent, OB = 10 cm and OA = 6 cm
Since tangent is perpendicular to the radius at its point of contact, $\angle$OAB = 90$^\circ$
Using Pythagoras theorem,
OB
2
= AB
2
+ OA
2
⇒ 10
2
= AB
2
+ 6
2
⇒ AB
2
= 64
⇒ AB = 8 cm
Hence, the correct answer is 8.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates Brochure
Your Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.
