Question : A tap can fill a cistern in 40 minutes and a second tap can empty the filled cistern in 60 minutes. By mistake without closing the second tap, the first tap was opened. In how many minutes will the empty cistern be filled?
Option 1: 72 minutes
Option 2: 84 minutes
Option 3: 108 minutes
Option 4: 120 minutes
Correct Answer: 120 minutes
Solution : Tap A fills $\frac{1}{40}$ part in 1 minute. Tap B empties $\frac{1}{60}$ part in 1 minute. Both pipe together in 1 minute can fill $=\frac{1}{40}-\frac{1}{60}=\frac{1}{120}$ part Thus, time taken to fill the tank = 120 minutes Hence, the correct answer is 120 minutes.
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Question : Taps A and B can fill a tank in 15 minutes and 10 minutes, respectively while tap C can empty the full tank in x minutes. If all three taps are opened together, the tank is filled completely in 8 minutes. Tap C alone will empty $\frac{3}{8}$ th part of the tank in:
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