Question : A thief is spotted by a policeman from a distance of 210 m. When the policeman starts the chase, the thief also starts running. If the speed of the thief is 25 km/hr and that of the policeman is 32 km/hr, then how far would the thief have run (in m) before he is overtaken?
Option 1: 920
Option 2: 480
Option 3: 1200
Option 4: 750
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Correct Answer: 750
Solution : Let the time taken to catch the thief be $x$ hour. Distance travelled by thief going at 25 km/hr = $25x$ Distance travelled by policeman going at 32 km/hr = $32x$ Now, distance travelled by thief + $\frac{210}{1000}$ = Distance travelled by policeman ⇒ $25x + \frac{210}{1000} = 32x$ ⇒ $x = \frac{30}{1000}$hours Distance travelled by thief going at 25 km/hours $=25x=25\times \frac{30}{1000}=\frac{3}{4}$ km $=$ 750 m Hence, the correct answer is 750.
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