A total energy of the body excuting s.h.m isE then the kinetic energy when displacement is half of the amplitude is
Answer (1)
Student Expert
15th Aug, 2019
Hey Kanhaiya!
Displacement= a/2
Total energy=1/2 m* (omega)^2* (a)^2 ....(1)
KE when displacement= x is
1/2 m* (omega)^2* [(a)^2-(x)^2]
1/2 m* (omega)^2* [(a)^2-(a/2)^2]
3/4(1/2*m* (omega)^2* (a)^2) .....(2)
By dividing 2 by 1, we get: 3/4
Therefore total fraction is 3/4
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