Question : A train starts from place S at 10: 00 a.m. and arrives at another place T at 2: 30 p.m. on the same day. If the speed of the train is 40 m/s, then what will be the distance covered by the train?
Option 1: 706 km
Option 2: 648 km
Option 3: 726 km
Option 4: 616 km
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Correct Answer: 648 km
Solution : Start time = 10:00 a.m. End time = 2:30 p.m. Speed = 40 m/s ⇒ Time = 2:30 p.m. – 10:00 a.m. = 4.5 hours = 16200 seconds ⇒ Distance = Speed × Time = 40 × 16200 = 648,000 meters = 648 km Hence, the distance covered by the train is 648 km. Hence, the correct answer is 648 km.
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