A uniform chainon smooth table and one third of its length is hanging over edge then work required to pull hanging part up is
Answer (1)
Student Expert
3rd Jul, 2019
Hello Stephy,
Suppose the length of an element at distance x from the table is dx. Let us consider that the mass of the hanging part is at the center of the gravity. Work done(W) is,
W = (M/L)*dx*g(x), where g(x) is x. Total work done to pull 1/3 part on the table.
W = integration of (M/L)*g(x)*dx with upper and lower limit as 1/3 and 0 respectively.
After solving. Work done(W) = MgL/18.
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