Question : ABC is an equilateral triangle with a side of 12 cm. What is the length of the radius of the circle inscribed in it?
Option 1: $2 \sqrt{3}$ cm
Option 2: $8 \sqrt{3}$ cm
Option 3: $4 \sqrt{3} $ cm
Option 4: $6 \sqrt{3}$ cm
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Correct Answer: $2 \sqrt{3}$ cm
Solution :
Given: ABC is an equilateral triangle with a side of 12 cm.
The length of the inradius of the equilateral triangle = $\frac{\text{side}}{2\sqrt3}=\frac{12}{2\sqrt3}=2\sqrt3$ cm
Hence, the correct answer is $2\sqrt3$ cm.
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