Question : A point D is taken from the side BC of a right-angled triangle ABC, where AB is hypotenuse. Then:

Question : ABC is a right angle triangle and $\angle ABC = 90^{\circ}$. BD is perpendicular on the side AC. What is the value of $(BD)^2$?

Question : In an isosceles triangle $ABC$, $AB = AC$ and $\angle A = 80^\circ$. The bisector of $\angle B$ and $\angle C$ meet at $D$. The $\angle BDC$ is equal to:

Question : If ABC is an equilateral triangle and D is a point in BC such that AD is perpendicular to BC, then:

Question : In a triangle ${ABC}, {D}$ is a point on ${BC}$ such that $\frac{A B}{A C}=\frac{B D}{D C}$. If $\angle B=68^{\circ}$ and $\angle C=52^{\circ}$, then measure of $\angle B A D$ is equal to: