Question : $\triangle$ABC is similar to $\triangle$DEF. If the area of $\triangle$ABC is 9 sq. cm and the area of $\triangle$DEF is 16 sq. cm and BC = 2.1 cm, then the length of EF will be:
Option 1: 5.6 cm
Option 2: 2.8 cm
Option 3: 3.7 cm
Option 4: 1.4 cm
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: 2.8 cm
Solution :
Given:
$\triangle$ABC is similar to $\triangle$DEF.
So, $\frac{\text{Area of ABC}}{\text{Area of DEF}}=\frac{BC^2}{EF^2}$
⇒ $\frac{9}{16}=\frac{2.1^2}{EF^2}$
⇒ $EF^2=\frac{4.41×16}{9}$
⇒ $EF=\sqrt{\frac{4.41×16}{9}}$
$\therefore EF =2.8$ cm
Hence, the correct answer is 2.8 cm.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
