a+b+c=0, then(aa/bc+bb/ca+cc/ab=?
Answer (1)
28th May, 2018
hello mdkafil
on the L.H.S. take the denominator's LCM being abc as a result the addition numerator would be a^3+b^3+c^3= (a+b+c)....
substituting the value of a+b+c =0 the value of req. result is 0.
hope it helps
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