Question : ABCD is a cyclic trapezium whose sides AD and BC are parallel to each other. If $\angle$ABC = $75^{\circ}$, then the measure of $\angle$BCD is:
Option 1: $75^{\circ}$
Option 2: $95^{\circ}$
Option 3: $45^{\circ}$
Option 4: $105^{\circ}$
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Correct Answer: $75^{\circ}$
Solution :
ABCD is a cyclic trapezium,
The two pairs of adjacent angles in a cyclic trapezium are equal in measure.
So, $\angle$ABC = $\angle$BCD = $75^{\circ}$.
Hence, the correct answer is $75^{\circ}$.
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