Question : ABCD is a cyclic trapezium whose sides AD and BC are parallel to each other. If $\angle$ABC = $75^{\circ}$, then the measure of $\angle$BCD is:
Option 1: $75^{\circ}$
Option 2: $95^{\circ}$
Option 3: $45^{\circ}$
Option 4: $105^{\circ}$
New: SSC CHSL tier 1 answer key 2024 out | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: $75^{\circ}$
Solution : ABCD is a cyclic trapezium, The two pairs of adjacent angles in a cyclic trapezium are equal in measure. So, $\angle$ABC = $\angle$BCD = $75^{\circ}$. Hence, the correct answer is $75^{\circ}$.
Candidates can download this e-book to give a boost to thier preparation.
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Question : $ABC$ is an isosceles triangle with $AB = AC$, The side $BA$ is produced to $D$ such that $AB = AD$. If $\angle ABC = 30^{\circ}$, then $\angle BCD$ is equal to:
Question : ABCD is a cyclic quadrilateral, AB is the diameter of the circle. If angle $\angle ACD=45^{\circ}$, then what is the value of $\angle BAD$?
Question : In $\triangle ABC$, $\angle B=60°$, $\angle C=40°$. AD is the bisector of $\angle A$ and AE is drawn perpendicular on BC from A. Then the measure of $\angle EAD$ is:
Question : If $ABCD$ is a cyclic quadrilateral with $\angle A=50^{\circ},\angle B=80^{\circ}$, then $\angle C$ and $ \angle D$ are:
Question : In $\triangle ABC, \angle B = 60^\circ$ and $\angle C = 40^\circ$, AD and AE are respectively the bisectors of $\angle A$ and perpendicular on BC. Find the measure of $\angle EAD$.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile