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ABCD is a parallelogram. P is any point on AD. CT is drawn perpendicular to PB. If PB=12 cm and CT=5cm determine the area of the parallelogram ABCD.


Prasad 24th Mar, 2020
Answer (1)
Mounika Sonti 29th May, 2020

Hello!!!!

Hope you are doing great!!!!

Consider P is the mid point of AD,and a line is drawn from P to B.

CT is the perpendicular drawn from C to line PB. ( assumed T is the centre of PB)

Area of paralellogram ABCD = bh sq.units

base = BC,,,,,,Height = AB

In triangle BTC ,,, CT=5,TB=6

From pythagorous theorm

BC^2= CT^2+TB^2

BC^2=5^+6^2

BC^2=61

BC=7.8

In Parallelogram the parallel sides are equal;

therefore BC=AD

In triangle ABP ,A/c to pythagorus theorm

BP^2=AP^2+AB^2     (AP=AD/2,AP=7.8/2),,,,,Given BP=12

12^2=(7.8/2)^2+AB^2

AB^2=144-15

AB^2=129

AB=11.3

Area of parallelogram = base*height

=BC*AB

=7.8*11.3

Area of parallelogram=88.14 cm^2

Hope it helps!!!!



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