Question : AD is the median of $\triangle$ABC. If O is the centroid and AO = 10 cm, then OD is:
Option 1: 5 cm
Option 2: 20 cm
Option 3: 10 cm
Option 4: 30 cm
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 5 cm
Solution : AD is the median of $\triangle$ABC. O is the centroid of the circle. The Centroid of the triangle divides the median into a 2 : 1 ratio. ⇒ $\frac{AO}{OD}=\frac{2}{1}$ ⇒ $\frac{10}{OD}=\frac{2}{1}$ $\therefore OD = 5$ cm Hence, the correct answer is 5 cm.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : AD is the median of triangle ABC. P is the centroid of triangle ABC. If AP = 14 cm, then what is the length of PD?
Question : $\triangle ABC$ is an equilateral triangle with a side of 12 cm and AD is the median. Find the length of GD if G is the centroid of $\triangle ABC$.
Question : In $\triangle A B C,\ D$ is the mid-point of $BC$ and $G$ is the centroid. If $G D = 10\ \text{cm} $, the length of $AD$ is_____.
Question : The centroid of a $\triangle ABC$ is G. The area of $\triangle ABC$ is 60 cm2. The area of $\triangle GBC$ is:
Question : $\triangle ABC \sim \triangle DEF$ and the perimeters of $\triangle ABC$ and $\triangle DEF$ are 40 cm and 12 cm respectively. If DE = 6 cm then AB is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile