Question : Ajay, Vijay, and Sashi can do a piece of work in 20, 40, and 60 days, respectively. In how many days can Ajay do the work if he is assisted by Vijay and Sashi on every fourth day?
Option 1: 15 days
Option 2: $\frac{50}{3}$ days
Option 3: $12$ days
Option 4: $\frac{44}{3}$ days
Correct Answer: $\frac{50}{3}$ days
Solution :
Ajay takes = 20 days
Vijay takes = 40 days
Sashi takes = 60 days
Vijay and Sashi assisted on every fourth day.
Total work = LCM(20, 40, 60) = 120 units
Efficiency of Ajay = $\frac{120}{20}$ = 6 units/day
Efficiency of Vijay = $\frac{120}{40}$ = 3 units/day
Efficiency of Sashi = $\frac{120}{60}$ = 2 units/day
Ajay's 3 days work = 6 × 3 = 18 units
Ajay, Vijay and Sashi one day work = 6 + 3 + 2 = 11 units
$\therefore$ Work done in 4 days = 18 + 11 = 29
$\therefore$ Work done in 16 days = 29 × 4 = 116 units
Remaining work = 120 – 116 = 4 units
Ajay done 4 units work in $\frac{4}{6}$ or $\frac{2}{3}$ days.
Total days taken by Ajay to complete the work if he is assisted by Vijay and Sashi on every fourth day
= 16 + $\frac{2}{3}$
= $\frac{50}{3}$ days
Hence, the correct answer is $\frac{50}{3}$ days.
Related Questions
Know More about
Staff Selection Commission Multi Tasking ...
Application | Cutoff | Selection Process | Preparation Tips | Eligibility | Exam Pattern | Admit Card
Get Updates Brochure
Your Staff Selection Commission Multi Tasking Staff Exam brochure has been successfully mailed to your registered email id “”.
