Question : Alloy X contains 70% copper and 30% zinc. Alloy Y contains 40% copper, 25% zine and 35% aluminium Alloy X and Y are mixed in the ratio of 1 : 3. What is the ratio of copper and zine in the newly formed alloy?
Option 1: 19 : 33
Option 2: 11 : 32
Option 3: 38 : 21
Option 4: 19 : 21
Correct Answer: 38 : 21
Solution :
Given ratio = 1 : 3
Let the weight of alloy X be 100 kg and the weight of alloy Y be 300 kg.
Weight of copper in alloy X = 70% of 100 = 70 kg
Weight of zinc in alloy X = 30% of 100 = 30 kg
Weight of copper in alloy Y = 40% of 300 = 120 kg
Weight of zinc in alloy Y = 25% of 300 = 75 kg
Share of copper in new alloy = $\frac{70+120}{100+300}$ = $\frac{190}{400}$
Share of zinc in new alloy = $\frac{30+75}{100+300}$ = $\frac{105}{400}$
Required ratio =$\frac{190}{400}:\frac{105}{400}$ = 190 : 105 = 38 : 21
Hence, the correct answer is 38 : 21.
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