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Question : Among three numbers, the first is twice the second and thrice the third. If the average of these three numbers is 396, then what is the difference between the first and the third number?

Option 1: 594

Option 2: 448

Option 3: 432

Option 4: 453


Team Careers360 24th Jan, 2024
Answer (1)
Team Careers360 25th Jan, 2024

Correct Answer: 432


Solution : Let the first number be $6x$, the second number be $3x$ and the third number $2x$.
The average of the three numbers = $\frac{6x+3x+2x}{3}=\frac{11x}{3}$
According to the question,
$\frac{11x}{3}=396$
$\therefore x=\frac{1188}{11}=108$
Difference between the first and the third number = $ 6x−2x=4x=4×108 = 432$
Hence, the correct answer is 432.

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