An automobile travelling with a speed of can brake to stop within a distance of 20m. If the car is going twice as fast, i.e., 120 Km/h, the stopping distance will be ________ m
Answer (1)
9th Apr, 2020
Hey,
since the speed is increased twice therefore initial speed is 120/2=60 km/hr.
now, there are two cases:
Case I:
given,
u=60 km/hr
v=0
S=20 m
Applying formula: v^2=u^2+2aS
0=(60*5/18)^2-(2*a*S)
a=(60*5/18)^2/(2*20)
Case 2:
u=120 km/hr
v=0
a=(60*5/18)^2/(2*20) (from case 1)
Applying the same formula as case 1
v^2=u^2+2aS
0=(120*5/18)^2+2*(60*5/18)/(2*20*S)
therefore
S=80 m, which is the required distance and answer.
I hope this helps.
All the best!
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