An electron in a one-dimensional infinite potential well, defined by V(x) = 0 for -a≤x≤a and V(x) = ∞ otherwise, goes from the n = 5 to the n = 2 level. The frequency of the emitted photon is 3.43 x 10^11 Hz. Find the width of the box.
Answer (1)
31st Mar, 2021
Hello candidate,
Due to a limitation on the number of answering modes available on the platform, it's not possible for me to provide you with the detailed answer but I can surely help you with the required steps.
First, the energy= -13.6× (z/n)^2 electron Volt, where N1 equals to 5 and N2 equals to 2. Then, use the equation of Energy= hc/ width, in order to calculate the width of the box.
Hope it helps!!
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