Question : An epidemic broke out in a village where 5% of the population died. Of the remaining population, 20% fled in panic. If the present population is 4655, what was the original population of the village?
Option 1: 6000
Option 2: 6125
Option 3: 5955
Option 4: 5995
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Correct Answer: 6125
Solution :
Let the village's initial population be 100$x$.
The population after death = 100$x$ – (5% of 100$x$) = 100$x$ – 5$x$ = 95$x$
After fleeing out, the population = 95$x$ – (20% of 95$x$)
= 95$x$ – ($\frac{20}{100}$ × 95) = 95$x$ – 19$x$ = 76$x$
According to the question,
76$x$ = 4655
⇒ $x$ = $\frac{4655}{76}$ = 61.25
So, the original population is (61.25 × 100) = 6125
Hence, the correct answer is 6125.
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