Question : An exterior angle of a triangle is 115° and one of the interior opposite angles is 45°. The other two angles are:
Option 1: 65° and 70°
Option 2: 60° and 75°
Option 3: 45° and 90°
Option 4: 50° and 85°
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Correct Answer: 65° and 70°
Solution : Given: $\angle$ACD = 115°, $\angle$BAC = 45° We know, $\angle$ABC + $\angle$CAB = $\angle$ACD ⇒ $\angle$ABC = 115° - 45° $\therefore$ $\angle$ABC = 70° $\angle$ACB + $\angle$BAC + $\angle$ABC = 180° ⇒ $\angle$ACB + 45° + 70° = 180° $\therefore$ $\angle$ACB = 180° – 70° – 45° = 65° Hence, the correct answer is '65° and 70°'.
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Question : If the sum and difference of two angles are 135° and $\frac{\pi}{12}$, respectively, then the value of the angles in degree measure is:
Question : If the angle of a right-angled triangle is 35°, then find the other angles.
Question : Possible measures of the three angles of a triangle are:
Question : In $\triangle$ABC, $\angle$B = 35°, $\angle$C = 65° and the bisector of $\angle$BAC meets BC in D. Then $\angle$ADB is:
Question : If $ABC \cong PQR$ and $\angle ABC = (x + 60)°$, $\angle PQR = (85 – 4x)°$, and $\angle RPQ = (3x + 65)°,$ then the value of $\angle ABC$ in degree is:
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