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an ideal gas is enclosed in a cylinder at pressure of 2atm and temperature,300k the mean time between two successive collisions is 6×10^-8.If the pressure is doubled and temperature is increased to 500k,the mean time between two successive collisions will be close to?


ismailmoin09 28th Jun, 2021
Answer (1)
ginnisachdeva02_9364270 Student Expert 28th Jun, 2021

Hi Aspirant!

As we know that,

t is directly proportional to (Volume/Velocity)

=> Volume is directly proportional to (T/P)

Therefore, t is directly proportional to [(sqr root T)/ P ]

Now, t1 / (6x10^-8) = [(sqr root 500)/2P ] * [P / (sqr root 300) ]

=> t1 = 3.8x10^-8

=> t1 ~= 4x10^-8 seconds

Hope it helps to clear your dilemma, thankyou!

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