an object moves along the circle with normal acceleration proportional to t power alpha. the power developed by all the forces acting on the object will have time dependence proportional to
Answer (1)
2nd Apr, 2020
Hello Aspirant !
As given by you in question , A = kt^x (K : Proportionality Quotient and x stands for alpha) ,
Normal Acceleration = v^2/R
Putting Acceleration value in it , v^2 = (kt^x)*R (R : Radius)
Kinetic Energy(E) = 1/2 mv^2 = 1/2*mkt^xR
Power P = dE/dt = d(1/2*mkt^xR) / dt
Hence , P = mkt2R
Hope it helps !
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