Question : $\triangle \mathrm{ABC}$ and $\triangle \mathrm{DEF}$ are similar triangles and their areas are 49 cm2 and 144 cm2 respectively, If $EF$ = 16.80 cm, then find $BC$.
Option 1: 7.5 cm
Option 2: 9.8 cm
Option 3: 8.7 cm
Option 4: 11.4 cm
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 9.8 cm
Solution : Given, $\triangle \mathrm{ABC}$ and $\triangle \mathrm{DEF}$ are similar triangles. $\therefore$ The ratio of their area will be equal to the ratio of squares of their lengths. ⇒ $\frac{49}{144} = \frac{\text{BC }^2}{(16.80)^2}$ ⇒ $\text{BC} = \sqrt{\frac{49}{144}\times(16.8)^2}$ ⇒ $\text{BC} =16.8\times \frac{7}{12}$ ⇒ $\text{BC} = 9.8\ \mathrm{cm}$ Hence, the correct answer is 9.8 cm.
Candidates can download this ebook to know all about SSC CGL.
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Question : For congruent triangles $\triangle$ABC and $\triangle$DEF, which of the following statements is correct?
Question : $\triangle \mathrm{ABC} \sim \triangle \mathrm{DEF}$ and the perimeters of these triangles are 32 cm and 12 cm, respectively. If $\mathrm{DE}=6 \mathrm{~cm}$, then what will be the length of AB?
Question : If $\triangle A B C \sim \triangle D E F$, and $B C=4 \mathrm{~cm}, E F=5 \mathrm{~cm}$ and the area of triangle $A B C=80 \mathrm{~cm}^2$, then the area of the $\triangle DEF$ is:
Question : If areas of similar triangles $\triangle {ABC}$ and $\triangle {DEF}$ are $ {x}^2 \ \text{cm}^2$ and $ {y}^2 \ \text{cm}^2$, respectively, and EF = a cm, then BC (in cm) is:
Question : $\triangle ABC \sim \triangle DEF$ and the perimeters of $\triangle ABC$ and $\triangle DEF$ are 40 cm and 12 cm respectively. If DE = 6 cm then AB is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile