Question : $\angle A, \angle B$ and $\angle C$ are three angles of a triangle. If $\angle A- \angle B=15^{\circ}, \angle B - \angle C=30^{\circ}$, then $\angle A, \angle B$ and $\angle C$ are:
Option 1: $80^{\circ},60^{\circ},$ and $40^{\circ}$
Option 2: $70^{\circ},50^{\circ},$ and $60^{\circ}$
Option 3: $80^{\circ},65^{\circ},$ and $35^{\circ}$
Option 4: $80^{\circ},55^{\circ},$ and $45^{\circ}$
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Correct Answer: $80^{\circ},65^{\circ},$ and $35^{\circ}$
Solution : Given that $\angle A - \angle B = 15^{\circ}$ and $\angle B - \angle C = 30^{\circ}$. $\angle A = \angle B + 15^{\circ}$ $\angle C = \angle B - 30^{\circ}$ We know that the sum of the angles in a triangle is $180^{\circ}$. $\angle A + \angle B + \angle C = 180^{\circ}$ Substituting the expressions for $\angle A$ and $\angle C$. $(\angle B + 15^{\circ}) + \angle B + (\angle B - 30^{\circ}) = 180^{\circ}$ ⇒ $3\angle B - 15^{\circ} = 180^{\circ}$ ⇒ $3\angle B = 195^{\circ}$ ⇒ $\angle B = 65^{\circ}$ Substituting $\angle B = 65^{\circ}$ into the expressions for $\angle A$ and $\angle C$, $\angle A = 65^{\circ} + 15^{\circ} = 80^{\circ}$ $\angle C = 65^{\circ} - 30^{\circ} = 35^{\circ}$ Hence, the correct answer is $80^{\circ}$, $65^{\circ}$, and $35^{\circ}$.
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