Question : In a $\triangle ABC$, if $\angle A=90^{\circ}, AC=5 \mathrm{~cm}, BC=9 \mathrm{~cm}$ and in $\triangle PQR, \angle P=90^{\circ}, PR=3 \mathrm{~cm}, QR=8$ $\mathrm{cm}$, then:

Option 1: $\triangle ABC \cong \triangle PQR$

Option 2: $ar(\triangle ABC)\neq ar(\triangle PQR)$

Option 3: $ar(\triangle ABC) \leq ar(\triangle PQR)$

Option 4: $ar(\triangle ABC)=ar(\triangle PQR)$

Question : In $\triangle$ABC and $\triangle$PQR, AB = PQ and $\angle$B = $\angle$Q. The two triangles are congruent by SAS criteria if:

Option 1: BC = QR

Option 2: AC = PR

Option 3: AC = QR

Option 4: BC = PQ

Question : If $\triangle \mathrm{ABC} \cong \triangle \mathrm{PQR}, \mathrm{BC}=6 \mathrm{~cm}$, and $\angle \mathrm{A}=75^{\circ}$, then which one of the following is true?

Option 1: $\mathrm{QR}=6$ cm, $\angle \mathrm{R}=75^{\circ}$

Option 2: $\mathrm{QR}=6$ cm, $\angle \mathrm{Q}=75^{\circ}$

Option 3: $\mathrm{QR}=6$ cm, $\angle \mathrm{P}=75^{\circ}$

Option 4: $\mathrm{PR}=6$ cm, $\angle \mathrm{P}=75^{\circ}$

Question : It is given that ABC $\cong$ PQR, AB = 5 cm, $\angle$B = $40^{\circ}$, and $\angle$A = $80^{\circ}$. Which of the following options is true?

Option 1: PQ = 5 cm and $\angle$R = $60^{\circ}$

Option 2: QR = 5 cm and $\angle$R = $60^{\circ}$

Option 3: QR = 5 cm and $\angle$Q = $60^{\circ}$

Option 4: PQ = 5 cm and $\angle$P = $60^{\circ}$

Question : Let ABC and PQR be two congruent triangles such that $\angle $A = $\angle $P = $90^{\circ}$. If BC = 13 cm, PR = 5 cm, find AB.

Option 1: 12 cm

Option 2: 8 cm

Option 3: 10 cm

Option 4: 5 cm