Question : Any six-digit number that is formed by repeating a three-digit number, is always divisible by:
Option 1: 111
Option 2: 1001
Option 3: 19
Option 4: 101
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: 1001
Solution : Let the six-digit number be of the form be 'abcabc'. The number can be expressed as: = 100000a + 10000b + 1000c + 100a + 10b + c = 100100a + 10010b + 1001c = 1001(100a + 10b + c) So, 1001 is a factor of 'abcabc' for any values of a, b and c. Hence, the correct answer is 1001.
Candidates can download this ebook to know all about SSC CGL.
Admit Card | Eligibility | Application | Selection Process | Preparation Tips | Result | Answer Key
Question : A six-digit number is divisible by 33. If 54 is added to the number, then the new number formed will also be divisible by:
Question : A 6-digit number has digits as consecutive natural numbers. The number is always divisible by
Question : If the sum of the digits of a three-digit number is subtracted from that number, then it will always be divisible by:
Question : In a 7-digit number 89476*2, what is the smallest possible value of * such that the number is divisible by 8?
Question : The largest four-digit number that is exactly divisible by 88 is:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile