AT 300K THE DENSITY OF A CERTAIN GASEOUS MOLECULE AT 2BAR IS DOUBLE TO THAT OF DINITROGEN(N2) AT 4BAR. THE MOLAR MASS OF GASEOUS MOLECULE IS
Answers (3)
P1V1=nRT
P2V2=n'RT
- n=dV1/M1 (d=density) ..............(1)
- n'=d'V2/28
- d=2*d'
(1) becomes
n=2*d'V1/M1;
P1V1=(2*d'V1/M1)*RT .................(2) {V1 gets cancelled}
P2V2=(d'V2/28)*RT.......................(3) {V2 gets cancelled}
taking (2)/(3):
P1/P2=(2/M1)/(1/28)
->2/4=56/M1
->M1=112g mol^(-1)
2 likes
Comments (0)
17th Jul, 2018
We know
PV=nRT ,
d1=d2,
P1×M1=P2×M2,
2×2m=4×28
m1=28 g mol^-1
Comments (0)
Related Questions
How to find bond order of a molecule?
127 Views
